Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float ans=0.0;
    int i=00,decimalPart=0;
    if(str[0]=='-'|| str[0]=='+') i=1;
    while(str[i]!='\0'){
        if(str[i]=='.') decimalPart=10;
        else if(decimalPart==0) ans=ans*10+str[i]-'0';
        else {
            ans = ans+1.0*(str[i]-'0')/decimalPart;
            decimalPart*=10;
        }
        i++;
    }
    return str[0]=='-'?-ans:ans;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach