Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float result = 0.0f; 
    float fraction = 0.0f; 
    float divisor = 10.0f;
    int sign =1; 
    uint8_t j=0; 
    uint8_t in_fraction =0; 

    if (str[0]=='-'){
        sign=-1; 
        j++;
    } else if (str[0]=='+') {
        sign=1; 
        j++;
    }

    while (str[j]!='\0') {
        if (str[j]=='.') {
            in_fraction=1; 
            j++;
            continue; 
        }
        if (str[j] >= '0' && str[j] <= '9') {
            int digit = str[j]-'0';
            if (!in_fraction) {
                result = result*10.0f+digit; 
            } else {
                fraction += digit/divisor;
                divisor*=10.0f;
            }
        } else {
            break;
        }
        j++;
    }

    return sign*(result+fraction);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach