Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>
#include <math.h>
float custom_atof(const char *str) {
    // Your logic here
    uint32_t ulNumber = 0;
    float finalNumber = 0;
    const char *dot_pos = NULL;
    uint8_t neg = 0;
    if(*str == '-')
    {
        neg = 1;
        str++;
    }
    else if(*str == '+')
    {
        str++;
    }
    while(*str != '\0')
    {
        if(*str == '.')
        {
            dot_pos = str;
        }
        else
        {
            ulNumber = ulNumber*10 + *str - '0';
        }
        str++;
    }
    if(dot_pos != NULL )
    finalNumber = (float)ulNumber /pow(10,str-dot_pos-1);
    else
    finalNumber = (float)ulNumber;

    return neg == 1? -finalNumber:finalNumber;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach