Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int sign =1,i=0,length=0;
    float result=0;
    if(str[0]=='-' || str[0] =='+')
    {
        if(str[0]=='-')
            sign = -1;
        i++;
    }
    int temp=0;
    while(str[i]!='\0')
    {
        if(str[i]>='0' && str[i]<='9')
            result = (result*10) +(str[i]-'0');
        
        if(str[i]=='.')
            temp =i;
        i++;
    }
    if(temp==0)
    {
        return sign*result;
    }
    else
    {
        temp++;
        while(str[temp]!='\0')
        {
            length++;
            temp++;
        }
        temp =1;
        while(length)
        {
            temp *=10;
            length--;
        }
        return (sign*(result/temp));
    }
    

    
}


int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach