Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    float num,dec=0;
    int i=0;
    if(str[0]=='+'||str[0]=='-'){i++;}
    while(str[i]!='.'&& str[i]!='\0'){
        num=num*10+(str[i++]-48);
    }
    i++;
    float f=0.1f;
    while(str[i]!='\0'){
        dec+=(str[i++]-48)*f;
        f=f*0.1f;
    }
    num=num+dec;
    if(str[0]=='+'){return num;}
    if(str[0]=='-'){return num*-1;}
    return num;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach