Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>
#include <cmath>

float custom_atof(const char *str) {
    // Your logic here
    int count = 0, sign = 1, point = 0, beforedec = 0, afterdec = 0, digitAfterDecimal = 1;
    float num = 0;
    if(str[count] == '+'){
        sign = 1;
        count++;
    }
    else if(str[count] == '-'){
        sign = -1;
        count++;
    }
    while(str[count]>='0' && str[count]<='9' || str[count]== '.'){
        if(str[count] == '.')
            point = 1;
        else if(!point){
            beforedec = beforedec * 10 + str[count] - '0';
        }else{
            num = num + (float)(str[count] - '0')/ pow(10,digitAfterDecimal);
            digitAfterDecimal++;
        }
        count++;
    }

    return  sign*(beforedec + num);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

 

 

 

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Input

123.45

Expected Output

123.45