Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
float result=0.0;
int sign =1;
float fraction =0.0;
float divisor=1.0;
if(*str=='-')
{
   sign=-1;
   str++;
}
else if(*str=='+')
{
    sign=1;
    str++;
}
while(*str>='0'&&*str<='9')
{
    result=result*10+(*str-'0');
    str++;
}
if(*str=='.')
{
    str++;

while(*str>='0'&&*str<='9')
{
    fraction=fraction*10+(*str-'0');
    divisor*=10;
    str++;
}
}
result=result+(fraction/divisor);
return sign*result;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach