Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i=0;
    float sign=1.0f;
    float result=0.0f;
    int is_frac=0;
    float frac_factor=0.1f;
    if(*(str+i) == '+'){
        i++;
    }
    else if (*(str+i) == '-'){
        sign=-1.0;
        i++;
    }

    while(*(str+i)!='\0'){
        if(*(str+i)=='.'){
            if(is_frac){
                break;
            }
            is_frac=1;

    }
    else if(*(str+i)>='0' && *(str+i)<='9'){
        if(!is_frac){
        result=result*10+(*(str+i)-'0');
        }
        else {
            result+=(*(str+i)-'0')*frac_factor;
            frac_factor*=0.1f;
        }
        }
        i++;
    }

    return sign*result;
}


int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach