Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i=0;float result=0.0f;int sign=1;float fraction=0.0f,divisior=1.0f;
    if(str[i] == '-')
    {
        sign = -1;
        i++;
    }
    else if(str[i] == '+')
    {
        sign = 1;
        i++;
    }
    while(str[i] >='0' && str[i] <= '9')
    {
        result = result * 10 + (str[i] - '0');
        i++;
    }
        if(str[i] == '.')
        {
             i++;
             while(str[i]>='0' && str[i] <= '9')
             {
                fraction = fraction*10 +(str[i] - '0');
                divisior*=10;
                i++;
             }
        }
      
    
    result = result + (fraction/divisior);
    return result * sign;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach