Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int sign=1;
    if(*str=='-'){
        sign=-1;
        str++;
    }
    if(*str=='+'){
        sign=1;
        str++;
    }
    int int_part=0;
    float fra=0.0f;
    while(*str!='.' && *str!='\0'){
        int_part=int_part * 10+(*str-'0');
        str++;
    }
    str++;
    float fac=0.1f;
    while(*str!='\0'){
        fra+=(*str-'0')*fac;
        fac*=0.1f;
        str++;
    }
    return sign*(int_part+fra);
    }
int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

simple pointer and conversion method guide from the quick guide