Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i =0;
    float result = 0.0f;
    float fraction = 0.0f;
    float divisor = 10.0f;
    float num = 0;
    int sign = 1;
    int flag_fraction = 0;
    if(str[i] == '-'){
        sign = -1;
        i++;
    }else if(str[i] == '+'){
        i++;
    }
    while(str[i] != '\0'){
        
        if(str[i] == '.'){
            flag_fraction = 1;
            i++;
            continue;
        }
        if(str[i] >= '0' && str[i] <= '9'){
            
            if(!flag_fraction){
              result = result *10.0f + (str[i] - '0');
            }else{
                fraction += (str[i] - '0')/ divisor;
                divisor *= 10.0f;        
            }
        }else{
            break;
        }
    
        i++;
    }
    return sign * (result + fraction);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach