Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i=0;
    float result=0;
    int sign=1;
    float divisor=0;
    if(str[0]=='-'||str[0]=='+'){
        if(str[0]=='-'){
            sign=-1;
        }
        i++;
    }
    while(str[i]>='0' && str[i]<='9'){
        result=result*10+(str[i]-'0');
        i++;
    }
    if(str[i]=='.'){
        i++;
        divisor=10;
        while(str[i]!='\0'){
            result= result + (str[i]-'0')/divisor;
            divisor*=10;
            i++;
        }
    }

    return result*sign;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach