Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>
#include <math.h>
float custom_atof(const char *str) {
    // Your logic here
    int i = 0, sign = 1;
    float num = 0.0f, divisor = 10.0f;
    if(str[i] == '-')
    {
        sign = -1;
        i++;
    }
    else if(str[i] == '+')
    {
        i++;
    }
    while(str[i] >= '0' && str[i] <= '9')
    {
        num = num * 10.0f + (str[i] - '0');
        i++;
    }
    if(str[i] == '.')
    {
        i++;
        while(str[i] >= '0' && str[i] <= '9')
        {
            num += (str[i] - '0')/divisor;
            divisor *= 10.0f;
            i++; 
        }
    } 
    return sign*num;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

 

 

 

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Input

123.45

Expected Output

123.45