Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here

    float result = 0.0f;
    float fration = 0.0f;
    float divisor = 10.0f;
    int sign = 1;
    uint8_t i = 0;
    uint8_t in_fraction = 0;

    if (str[i] == '-'){
        sign = -1;
        i++;
    } else if (str[i] == '+'){
        sign = 1;
        i++;
    }

    while (str[i] != '\0'){
        if (str[i] == '.'){
            in_fraction = 1;
            i++;
            continue;
        }

        if (str[i] >= '0' && str[i] <= '9'){
            if (!in_fraction) {
                result = result*10 + (str[i] - '0');
            } else {
                fration += (str[i] - '0') / divisor;
                divisor *=10.0f;
            }
        } else {
            break;
        }
        i++;
    }

    return sign*(result + fration);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach