Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    uint8_t i = 0;
    float divisor = 10;
    float num = 0, decimal = 0;
    int sign = 1;

    if (str[0] == '-') {
        sign = -1;
    }

    while (str[i] != '\0') {
        if (str[i] >= '0' && str[i] <= '9') {
            num = (num * 10) + (str[i] - '0');
        } else if (str[i] == '.') {
            i++;

            while (str[i] >= '0' && str[i] <= '9') {
            decimal = (decimal) + (float)((str[i] - '0') / (divisor));
            divisor = divisor * 10;
            i++;
            }   
            break;
        }
        i++;
    }
    return (sign *(num+decimal));
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

123.45

Expected Output

123.45