Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float result = 0.0;
    int i = 0;
    int sign = 1;
    if (str[0] == '-'){
        sign = -1;
        i++;
    } else if (str[0] == '+') i++;
    while (str[i] >= '0' && str[i] <= '9'){
        result = result * 10 + (str[i] - '0');
        i++;
    }
    if (str[i] == '.'){
        i++;
        float div = 10.0;
        while (str[i] >= '0' && str[i] <= '9'){
            result = result + (str[i] - '0') / div;
            div *= 10;
            i++; 
        } 
    }
    return result * sign;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach