Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int sign = 1;
    int num = 0.0f;
    float dec = 0.0f;
    bool is_dot = false;
    int divisor = 1;

    if(*str == '+' || *str == '-')
    {
        if(*str == '-')
        {
            sign = -1;
        }
        str++;
    }

    while(*str != '\0')
    {
        if((is_dot == false) && (*str != '.'))
        {
            num = (num * 10) + ((*str) - '0');
        }
        else if(*str == '.')
        {
            is_dot = true;
        }
        else
        {
            dec = dec * 10 + (*str - '0');
            divisor *= 10;
        }
        str++;
        
    }
    return (sign * (num + dec/divisor));
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach