Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#include <math.h>

float custom_atof(const char *str) {
    // Your logic here
    int sign = 1;
    int indx = 0;
    if(str[indx] == '-')
    {
        sign = -1;
        indx++;
    }
    else if(str[indx] == '+')
    {
        sign = 1;
        indx++;
    }
    

    int before_decimal = 0;

    while(str[indx] != '.' && str[indx] != '\0')
    {
        before_decimal = before_decimal * 10 + (str[indx] -'0');
        indx++;
    }
    if(str[indx] == '\0')
    {
        return (float) before_decimal;
    }

    int after_decimal = 0;
    int decimal_points = 0;
    indx++;
    while(str[indx] != '\0')
    {
        after_decimal = after_decimal * 10 + (str[indx] - '0');
        indx++;
        decimal_points++;
    }

    return sign * (before_decimal + ((float) after_decimal) / pow(10, decimal_points));

    

}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach