Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float num = 0, divise = 1;

    int i = 0, sign = 1;
    if (str[i] == '-'){
        ++i; sign = -1;
    } else if (str[i] == '+') ++i;
    while (str[i] != '\0'){
        if (str[i] >= '0' && str[i] <= '9') num = num*10 + (str[i] - '0');
        if (str[i] == '.'){
            int j = i + 1;
            while (str[j] != '\0'){
                divise = divise*10; ++j;
            }
        }
        ++i;
    }
    return sign*num / divise;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

 

 

 

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Input

123.45

Expected Output

123.45