Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i = 0, sign = 1;
    float res = 0;
    if (str[i] == '-'){
        sign = -1;
        ++i;
    } else if (str[i] == '+') ++i;

    int divise = 1;
    while (str[i] != '\0'){
        if (str[i] >= '0' && str[i] <= '9') res = res * 10 + (str[i] - '0');
        if (str[i] == '.'){
            int j = i + 1;
            while (str[j] != '\0') {
                divise = divise*10;
                ++j;
            }    
        }
        ++i;
    }
    return sign * res / (divise);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach