Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int sign = 1;
    bool dot = false;
    int cnt = 1;
    float ret1 = 0;
    float ret2 = 0;
    if ( '-' == *str) {
        sign = -1;
        str++;
    } else if ('+' == *str) {
        str++;
    }

    while (0 != *str) {
        if ('.' == *str) {
            dot = true;
        } else if (!dot) {
            ret1 = ret1 * 10 + *str - '0';
        } else if (dot) {
            ret2 = ret2 * 10 + *str - '0';
            cnt *= 10;
        }
        str++;
    }

    return sign * (ret1 + ret2 / cnt);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

my logic is similar to the solution