Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int number=0;
    int neg=0;
    float fraction=0;
    int after_fraction=0;
    float divisor=10.0;
    if( *str == '-')
    {
        neg=1;
        str++;
    }
    else if( *str == '+')
    {
        str++;
    }
    while( *str ) 
    {
        if( *str == '.')
        {
            after_fraction =1;
        }
        else if(after_fraction==0)
        {
            number=(number*10)+( *str - '0');
        }
        else
        {
            fraction=fraction + ( *str - '0')/divisor;
            divisor *= 10.0;

        }
        str++;
    }
    float ans=number+fraction;
    if(neg)
    {
        return -(ans);
    }
    else
    {
        return ans;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

 

 

 

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Input

123.45

Expected Output

123.45