Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i=0,sign=1,f=0;
    float result=0.0,fraction=0.0,divisor=1.0;
    while(str[i]==' ')i++;
    if(str[i]=='-'){
         sign=-1;
         i++;
    }
    else if(str[i]=='+'){
       i++;
    }
    while((str[i]>='0'&&str[i]<='9')||str[i]=='.'){
    if(str[i]=='.'){
       i++;
        f=1;
    }
    if(!f){
        result=result*10+(str[i]-'0') ;
        i++;}
    else if(f){
       fraction = fraction * 10 + (str[i] - '0');
            divisor *= 10;
            i++;
    }
    
    
}result +=fraction/divisor;
return sign *result;
}
int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach