Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i=0,sign=1,pos=0;
    float num=0;
    if(str[i]=='+') {
        sign=1;
        i++;}
    else if(str[i]=='-') {
        sign=-1;
        i++;}
    
    while(str[i]!='\0'){
       if(str[i]=='.'){
        pos=i;
       } 
       else if(str[i]>='0' && str[i]<='9'){
           num=(num*10)+(str[i]-'0');
       }
       i++;
    }
    if(pos>=1){
    pos=i-pos;
    pos--;
    for (i=0;i<pos;i++){
        num/=10;
    }}
    return (sign*num);
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach