Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i=0,sign=1,num=0,num2=1,on=0;
    while(str[i]!='\0'){
        if (i==0 && (str[i]=='+' || str[i]=='-')) {
            if(str[i]=='-') sign =-1;
        }
        else {
            if (str[i]=='.'){
                 on =1;
            }
            else{
                 num=(num*10)+str[i]-'0';
                 if (on==1) num2*=10;
            }
        }
        i++;
    }
    float ans = (float)(num*sign)/num2;
    return ans;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach