Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float result = 0.0f;
    float fraction = 0.0f;
    int sign = 1;
    int i = 0;
    int decimal_found = 0;
    int decimal_places = 0;

    while(str[i] == ' ' || str[i] == '\t') {
        i++;
    }

     if(str[i] == '+') {
        sign = 1;
        i++;
    }
    else if(str[i] == '-') {
        sign = -1;
        i++;
    }

    while(str[i] != '\0') {
        if(str[i] >= '0' && str[i] <= '9') {
            if(!decimal_found) {
                result = result * 10.0f + (str[i] - '0');
            } else {
                fraction = fraction * 10.0f + (str[i] - '0');
                decimal_places++;
            }
        }
        else if(str[i] == '.') {
            if(decimal_found) break;  // Second decimal point? Stop
            decimal_found = 1;
        }
        else {
            break;  // Stop at any other character
        }
        i++;
    }
    for(int j = 0; j < decimal_places; j++) {
        fraction /= 10.0f;
    }
    
    result = result + fraction;
    
    return sign * result;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach

 

 

 

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Input

123.45

Expected Output

123.45