Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    int i = 0; float div = 10;
    int b_dec = 1;
    float value;
    while(str[i] != '\0')
    {
        if(str[i] == '.')
        {
            b_dec = 0; 
        }
        else if(b_dec)
        {
            if(str[0] == '-')
            {
                if(str[i]>='0' && str[i]<='9')
                    value = value*10 - (str[i] - 48);
            }    
            else {
                if(str[i]>='0' && str[i]<='9')
                    value = value*10 + (str[i] - 48);
            }
            
        }
        else
        {
            if(str[0] == '-')
                value = value - (float)(str[i] - 48)/div;
            else{
                value = value + (float)(str[i] - 48)/div;
            }
            div*=10;
        }
        i++;
    }
    return value;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach