Convert a String to Float

Code

#include <stdio.h>
#include <stdint.h>

float custom_atof(const char *str) {
    // Your logic here
    float pre = 0;
    float at = 0;
    int cnt = 1;
    int sign = 1;

    if(*str == '-'){
        sign = -1;
        str++;
    }
    else if(*str == '+'){
        sign = 1;
        str++;
    }
    
    while(*str != '\0'){
        if(*str == '.'){
            str++;
            while(*str != '\0'){
                at = at * 10 + (*str - '0');
                cnt *= 10;
                str++;
            }
        }
        else if(*str >= '0' && *str <= '9'){
            pre = pre * 10 + (*str - '0');
        }
        str++;
    }

    return (pre + (at / cnt)) * sign;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    float value = custom_atof(str);
    printf("%.2f", value);
    return 0;
}

Solving Approach