Convert Decimal Number to Binary or Hex Without itoa function

Code

#include <stdio.h>
#include <stdint.h>

void print_base(uint16_t num, uint8_t base) {
    // Your logic here
    char buffer[17]; // Enough for 16-bit binary + null terminator
    int i = 0;

    if (num == 0) {
        printf("0\n");
        return;
    }

    while (num > 0) {
        uint8_t digit = num % base;
        buffer[i++] = (digit < 10) ? ('0' + digit) : ('A' + digit - 10);
        num /= base;
    }

    // Print in reverse order
    for (int j = i - 1; j >= 0; j--) {
        putchar(buffer[j]);
    }
    putchar('\n');
    
}

int main() {
    uint16_t num;
    uint8_t base;
    scanf("%hu %hhu", &num, &base);

    print_base(num, base);
    return 0;
}

Solving Approach

• Handle Zero Case
• If num == 0, print "0" and return
• Initialize a Buffer
  • Use a char buffer[] to store digits in reverse order
  • Use an index i = 0 to track buffer position
• Loop Until num Becomes Zero
  • In each iteration:
• digit = num % base
• Convert digit to character:
  • If digit < 10: '0' + digit
  • Else: 'A' + digit - 10 (for hex digits)
• Store character in buffer
• num = num / base
• Print Buffer in Reverse
• Loop from i - 1 down to 0 and print each character