Convert Decimal Number to Binary or Hex Without itoa function

Code

#include <stdio.h>
#include <stdint.h>

void print_base(uint16_t num, uint8_t base) {
    // Your logic here
    if(num==0){
        printf("0");
    }
    else if(base==2){
        int arr[100],index=0;
        while(num>0){
            arr[index]=num%2;
            num/=2;
            index+=1;
        }
    for(int i=index-1;i>=0;i--){
        printf("%d",arr[i]);
    }
    }
    else{
        char arr[100];
        int index=0;
        while(num>0){
            int y=num%16;
            if(y>=10){
                arr[index]=y==10?'A':y==11?'B':y==12?'C':y==13?'D':y==14?'E':'F';
            }
            else{
                arr[index]=y==1?'1':y==2?'2':y==3?'3':y==4?'4':y==5?'5':y==6?'6':y==7?'7':y==8?'8':'9';
            }
            index+=1;
            num/=16;
        }
          for(int i=index-1;i>=0;i--){
                printf("%c",arr[i]);
            }
    }
}

int main() {
    uint16_t num;
    uint8_t base;
    scanf("%hu %hhu", &num, &base);

    print_base(num, base);
    return 0;
}

Solving Approach

simple looping and ternery operator helped me to solve the problemm