Convert Decimal Number to Binary or Hex Without itoa function

Code

#include <stdio.h>
#include <stdint.h>


void print_binary_format(uint16_t num)
{
    if(num == 0)
    {
        printf("0\n");
    }

    char bits[17];
    int end = 15;
    while(num > 0)
    {
        bits[end] = (num & 1U) ? '1' : '0';
        end--;
        num >>= 1;
    }

    bits[16] = '\0';
    printf("%s\n", &bits[end+1]);
}

char getHex(uint8_t value)
{
    if(value >=0 & value <= 9)
    {
        return '0' + value;
    }
    else
    {   
        return 'A' + (value - 10);
    }
}

void print_hex_foramt(uint16_t num)
{
    char hex[5];
    for(int i=0; i<4; i++)
    {
        hex[i] = '0';
    }
    hex[4] = '\0';
    uint8_t end = 3;
    while(num > 0)
    {   
        char temp =  getHex(num & 0xF);
        hex[end] = temp;
        end--;
        num >>= 4;

    }
   
    printf("%s \n", &hex[end+1]);

}

void print_base(uint16_t num, uint8_t base) {
    // Your logic here

    if(base == 2)
    {
        print_binary_format(num);
    }
    else if(base = 16)
    {
        print_hex_foramt(num);
    }
}

int main() {
    uint16_t num;
    uint8_t base;
    scanf("%hu %hhu", &num, &base);

    print_base(num, base);
    return 0;
}

Solving Approach