Convert Decimal Number to Binary or Hex Without itoa function

Code

#include <stdio.h>
#include <stdint.h>

void print_base(uint16_t num, uint8_t base) {
    // Your logic here
    uint16_t temp[200];
    int cnt=0;

    char hex[] = "0123456789ABCDEF";

    if (num==0){
        printf("0");
        return;
    }

    
    if (base==2){
    while (num>0){
          temp[cnt++]=num%2;
          num/=2;
          
    }
    }
    else {
        while (num>0){
          temp[cnt++]=hex[num%16];
          num/=16;
          
    }

    }

    for (int i=0;i<cnt;i++){
        if (base==2){
        printf("%c",temp[cnt-1-i]+'0');
        }
        else {
        printf("%c",temp[cnt-1-i]);
        }
    }

   
}

int main() {
    uint16_t num;
    uint8_t base;
    scanf("%hu %hhu", &num, &base);

    print_base(num, base);
    return 0;
}

Solving Approach