Convert Integer to Hex String Without sprintf or itoa functions

Code

#include <stdio.h>
#include <stdint.h>

void print_hex(uint16_t num) {
    // Your logic here
    char str[4];
    int count=0;
    if(num == 0)
        printf("0");
    for(int i=0;(num >> 4*i)>0;i++){
        if(((num >> 4*i) & 0xF) >= 0 && ((num >> 4*i) & 0xF) <= 9){
            str[i] = ((num >> 4*i) & 0xF) + '0';
            count++;
        }
        else if(((num >> 4*i) & 0xF) >= 10 && ((num >> 4*i) & 0xF) <= 15){
            str[i] = ((num >> 4*i) & 0xF) + 'A' - 10;
            count++;
        }

    }
    for(int j=0;j<count;j++){
        printf("%c", str[count-j-1]);
    }
}

int main() {
    uint16_t num;
    scanf("%hu", &num);
    print_hex(num);
    return 0;
}

Solving Approach