Convert Integer to Hex String Without sprintf or itoa functions

Code

#include <stdio.h>
#include <stdint.h>

void print_hex(uint16_t num) {
    // Your logic here
    char hex[5];
    int i;
    for(i=3;i>=0;i--)
    {
        int digit=num&0xf;
        if(digit<10)
        hex[i]='0'+digit;
        else 
        hex[i]='A'+digit-10;
        num>>=4;
    }
    hex[4]=0;

    int start=0;
    while(start < 3 && hex[start]=='0')
    start++;
    printf("%s\n",&hex[start]);
}

int main() {
    uint16_t num;
    scanf("%hu", &num);
    print_hex(num);
    return 0;
}

Solving Approach

char hex[5];
    int i;
    for(i=3;i>=0;i--)
    {
        int digit=num&0xf;
        if(digit<10)
        hex[i]='0'+digit;
        else 
        hex[i]='A'+digit-10;
        num>>=4;
    }
    hex[4]=0;

    int start=0;
    while(start < 3 && hex[start]=='0')
    start++;
    printf("%s\n",&hex[start]);