Convert Integer to Hex String Without sprintf or itoa functions

Code

#include <stdio.h>
#include <stdint.h>

void print_hex(uint16_t num) {
    // Your logic here
    if(num == 0)
    {
        printf("0");
        return;
    }

    char hex[16] = {'0', '1', '2', '3', '4', '5', '6', '7', 
                    '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};

    char result[4] = {'0', '0', '0', '0'};
    int i = 0;

    while(num)
    {
        result[i++] = hex[(num % 16)];
        num /= 16;
    }

    for(int j = i-1; j >= 0; j--)
    {
        printf("%c", result[j]);
    }
}

int main() {
    uint16_t num;
    scanf("%hu", &num);
    print_hex(num);
    return 0;
}

Solving Approach