Convert String to Integer

Code

#include <stdio.h>
#include <stdint.h>

int custom_atoi(const char *str) {
    // Your logic here
    int val=0,nagative=0,count=0,val_count=0;
    while(*str!='\0')
    {
        // printf("*str=%c \n",*str);
        if(*str=='-')
        {
            nagative=1;
            val_count++;
        }
        else if(*str=='+')
        {
            val_count++;
        }
        else if((*str>='0')&&(*str<='9'))
        {
            if(count!=val_count) break;
            val = (val*10)+(uint8_t)(*str-'0');
            val_count++;
            // printf("val=%d\n",val);
        }
        else
        {     
            if((*str!='+')&&(val==0))
            {
                return 0;
            }            
        }
        str++;
        count++;
    }
    return (nagative==1)?0-val:val;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    printf("%d", custom_atoi(str));
    return 0;
}

Solving Approach