Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    char c;
    while ((*str) != '\0') {
        c = *str;
        if ((c >= 'a') && (c <= 'z')) {
            *alpha +=1;
        }
        else if ((c >= 'A') && (c <= 'Z')) {
            *alpha += 1;
        }
        else if ((c >= '0') && (c <= '9')) {
            *digit += 1;
        }
        else  if ( c != ' ') {
            *symbol += 1;
        }
        str++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

count chars between 'a' and 'z' and between 'A' and 'Z'

count digits between '0' and '9'

count the others if not space ' '