Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>


uint8_t isAlphabet(char c)
{
    for(char i='A';  i<='Z'; i++)
    {
        if(c==i)
        {
            return 1;
        }
    }


    for(char i='a';  i<='z'; i++)
    {
        if(c==i)
        {
            return 1;
        }
    }

    return 0;    
}

uint8_t isDigit(char c)
{
      for(char i='0' ;  i<='9'; i++)
    {
        if(c==i)
        {
            return 1;
        }
    }



    return 0;     
}


void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
   
   uint8_t digitCounter = 0, alphaCounter = 0, symbolCounter=0;

    // loop through str
   for(int i=0; str[i]!='\0'; i++)
   {
        if(isAlphabet(str[i]))
        {
            alphaCounter++;
        }

        else if(isDigit(str[i]))
        {
            digitCounter++;
        }

        else
        {
            if(str[i]!=' ')
            symbolCounter++;
        }
   }

   *alpha  = alphaCounter;
   *digit  = digitCounter;
   *symbol = symbolCounter;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach