Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int start =0, end =0;
    while(*(str+end)!='\0') end++;

    while(start < end)
    {
        // printf("start=%d end=%d *alpha=%d *digit=%d *symbol=%d\n",start,end,*alpha,*digit,*symbol);        
        if(48<=((uint8_t)*str)&&(57>=(uint8_t)*str)) // digit
        {
            (*digit)++;
            // printf("digit = %d\n",(uint8_t)*str);
        }
        else if((65<=((uint8_t)*str)&&(90>=(uint8_t)*str))||(97<=((uint8_t)*str)&&(122>=(uint8_t)*str))) // alpha
        {
            (*alpha)++;
            // printf("alpha = %d\n",(uint8_t)*str);
        }
        else if(32!=((uint8_t)*str))
        {
           (*symbol)++; 
        }
        str++;
        start++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2