Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    *alpha = 0;
    *digit = 0;
    *symbol = 0;
    while (*str != '\0'){
        if((*str >= 'a' && *str <= 'z') || (*str >= 'A' && *str <= 'Z'))
            (*alpha)++;
        else if (*str >= '0' && *str <= '9')
            (*digit)++;
        else if (*str == 32){
            str++;
            continue;
        }
            
        else
            (*symbol)++;
        
        str++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach