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Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
     int a=0,b=0,c=0;
    for(int i=0;str[i]!='\0';i++)
    {
        if((str[i]>='a' && str[i]<='z' )|| (str[i]>='A' && str[i]<='Z'))
        {
           a++;
           *alpha=a;
        }
        else if(str[i]>='0' && str[i]<='9')
        {
            b++;
          *digit=b;  
        }
        else{
            if(str[i]==' ')
            {
                continue;
            }
            c++;
         *symbol=c;   
        }
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2