95. Count Alphabets Digits and Symbols in a String

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Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int i=0;
    while(str[i]!='\0'){
        //1. Make current char into ASCII uint8_t value
        uint8_t cur_char = (uint8_t)str[i];
        //printf("%u\n",cur_char);

        //2. Check if ASCII value is within the range of Alphabet (A-Z, a-z)
        if((cur_char >= 65 && cur_char <= 90) || (cur_char >= 97 && cur_char <= 122)){
            (*alpha)++; //Incremenet pointer value of alpha
        }
        //3. Check ASCII values for digits
        else if((cur_char >= 48 && cur_char <= 57)){
            (*digit)++;
        }
        //4. Check for any other symbols apart from space
        else if(cur_char!= 32){
            (*symbol)++;
        }
        i++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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