Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int len;
    for(len=0;str[len]!='\0';len++);

    int i;
    for(i=0;i<len;i++){
        if(str[i] >= '0' && str[i]<='9') {
            (*digit)++;
            //printf("%c",str[i]);
        }
        else if((str[i] >='a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z')) (*alpha)++;
        else if(str[i] != ' ') (*symbol)++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2