Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int count_digit = 0;
    int count_symbol = 0;
    int count_alpha =0;
    for(int i =0; str[i] != '\0'; i ++){
        if(*(str + i) >= '0' && *(str + i) <= '9' ){
            count_digit++;
        }else if(*(str + i) >= 'a' && *(str + i) <= 'z'||*(str + i) >= 'A' && *(str + i) <= 'Z' ){
            count_alpha++;
        }else{
            if(*(str + i) != ' '){
                count_symbol++;
            }
        }
    }
    *digit = count_digit;
    *alpha = count_alpha;
    *symbol = count_symbol;
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2