Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int index = 0;
    while(str[index] != '\0'){
        // if ((str[index] >= 0 && str[index] <= 47) || (str[index] >= 58 && str[index] <= 64) || (str[index] >= 91 && str[index] <= 96) || (str[index] >= 123 && str[index] <= 255)) (*symbol)++;
        if (str[index] >= 48 && str[index] <= 57) (*digit)++;
        if (str[index] >= 65 && str[index] <= 90 || str[index] >= 97 && str[index] <= 122) (*alpha)++;
        if ((str[index] >= 33 && str[index] <= 47) || (str[index] >= 58 && str[index] <= 64) || (str[index] >= 91 && str[index] <= 96) || (str[index] >= 123 && str[index] <= 255)) (*symbol)++;

        index++;
    }

}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach