Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    uint8_t i = 0;
    while (str[i]) {
        char temp = str[i];
        if (temp == ' ') {
            i++;
            continue;  // Skip spaces
        }

        if((temp >= 'A' && temp <= 'Z')  || (temp>='a' && temp<='z')){
            (*alpha)++;
        }                    
        else if(temp >= '0' && temp <= '9'){
            (*digit)++;
        }            
        else{
            (*symbol)++;
        }
                    
        i++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

1. Skip spaces, then check each character: if it's alphabetic (A–Z or a–z), digit (0–9), or symbol (everything else).
2. Increment counters accordingly using (*alpha)++, (*digit)++, or (*symbol)++.