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Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

#define AZ_START ('A')
#define AZ_END ('Z')
#define az_START ('a')
#define az_END ('z')
#define DIGITS_START ('0')
#define DIGITS_END ('9')
#define SPACE (' ')


void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    while(*str)
    {
        if(((*str >= AZ_START) && (*str <= AZ_END)) ||
            (((*str >= az_START) && (*str <= az_END))))
        {
            (*alpha)++;
        }
        else if((*str >= DIGITS_START) && (*str <= DIGITS_END))
        {
            (*digit)++;
        }
        else
        {
            if(*str != SPACE)
            {
                (*symbol)++;
            }
            
        }
        str++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2