Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    *alpha = 0;
    *digit = 0;
    *symbol = 0;
    int i = 0;
    while(str[i] != '\0'){
     char ch = str[i];
     if( (ch <= 'Z' && ch >= 'A') || ch <= 'z' && ch >= 'a'){
        (*alpha)++;
     }else if(ch <= '9' && ch >= '0'){
        (*digit)++;
     }else if(ch != ' '){
        (*symbol)++;
     }
     i++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach