Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    while(*str!='\0'){
        char ch = *str;
        if((ch>='A' && ch<='Z') || (ch>='a' && ch<='z'))
            *alpha = *alpha+1;
        else if(ch>='0' && ch<='9')
            *digit = *digit+1;
        else if(ch!=' ')  
            *symbol = *symbol+1;
        str++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2