Count Alphabets Digits and Symbols in a String

Code

#include <stdio.h>
#include <stdint.h>

void classify_chars(const char *str, uint8_t *alpha, uint8_t *digit, uint8_t *symbol) {
    // Your logic here
    int i=0;
    *alpha=0;
    *digit=0;
    *symbol=0;
    while(*(str+i)!='\0'){
        char ch=*(str+i);
        if (ch>='A' && ch<='Z' || ch>='a' && ch <= 'z')
            (*alpha)++;
        
        else if(ch>='0' && ch<='9')
            (*digit)++;

        else if(ch==' ') ;       

        else    
            (*symbol)++;
        i++;
    }
}

int main() {
    char str[101];
    fgets(str, sizeof(str), stdin);

    // Remove newline
    uint8_t i = 0;
    while (str[i]) {
        if (str[i] == '\n') {
            str[i] = '\0';
            break;
        }
        i++;
    }

    uint8_t alpha = 0, digit = 0, symbol = 0;
    classify_chars(str, &alpha, &digit, &symbol);
    printf("Alphabets = %u\nDigits = %u\nSymbols = %u", alpha, digit, symbol);
    return 0;
}

Solving Approach

 

 

 

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Input

C99_Firmware!

Expected Output

Alphabets = 9 Digits = 2 Symbols = 2